How to Solve Equations with Unknown Variables Using Trigonometric Identities

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Homework Help Overview

The discussion revolves around solving an equation involving unknown variables and trigonometric identities, specifically using Euler's formula. The original poster is attempting to manipulate the equation to find a solution, particularly focusing on the relationship between imaginary numbers and trigonometric expressions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Euler's formula to rewrite the equation and explore the implications of the product of exponential terms. Questions arise regarding the correct interpretation of the factors and the role of the imaginary unit in the equation.

Discussion Status

Some participants have provided guidance on using Euler's formula and have confirmed certain mathematical identities. There is an ongoing exploration of how to derive the necessary values and the implications of periodic solutions, indicating a productive exchange of ideas without a clear consensus yet.

Contextual Notes

Participants are navigating the complexities of the equation, including the need to clarify assumptions about the variables and the nature of the solutions required. The discussion reflects a mix of certainty and uncertainty regarding the mathematical steps involved.

cdummie
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Homework Statement


I have to solve the following equation:
Screenshot_1.jpg


Homework Equations

The Attempt at a Solution


I know that since the right side is 1 and on the left side i have i (imaginary number) it means that i could rewrite right side as cos0 + isin0 since it's the same, but what can i do with left side, it obviously can't stay like this because of the product, i have to get rid of it, i just don't have an idea.
 
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What do you get when you replace the factors in the product using Euler's formula?
 
Samy_A said:
What do you get when you replace the factors in the product using Euler's formula?

As far as i know, we have Пekx (П is from 1 to n) which is equal to:

ex*e2x*...*enx or

e(1+2+...+n)x. Now, i am not 100% sure, but i believe is should represent 1+2+...+n as n(n+1)/2 and go back to the trigonometric form of number, and then simply find x since i know exact value of angle for the right side. Am i correct?
 
cdummie said:
As far as i know, we have Пekx (П is from 1 to n) which is equal to:

ex*e2x*...*enx or

e(1+2+...+n)x. Now, i am not 100% sure, but i believe is should represent 1+2+...+n as n(n+1)/2 and go back to the trigonometric form of number, and then simply find x since i know exact value of angle for the right side. Am i correct?
You forgot the ##i## in your exponent, as Euler's formula is ##cos(y)+isin(y)=e^{iy}##.
You are correct about ##\sum_{k=1}^n k =n(n+1)/2##.
As the product is equal to ##1##, you can now indeed solve for x by applying Euler's formula again: the cosine of your exponent (not including the ##i##) must be ##1##.
 
Last edited:
How many solutions do you need? Just one, all of them for a fixed n, or all of them for any n?
##e^{iy} = 1 ## is true for an infinite number of periodic terms.
For a large w, ##e^{iwy} ## will have a much shorter period. Your w might get quite large as n grows.
 

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