Can you solve for x in this equation?

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To solve the equation 4x^2 + x = 0, factor out the common variable x, resulting in x(4x + 1) = 0. This leads to two potential solutions: x = 0 and 4x + 1 = 0. Solving 4x + 1 = 0 gives x = -1/4 or -0.25. The discussion highlights the factoring method and confirms the solutions through basic algebraic principles. Ultimately, the equation can be solved effectively by recognizing common factors.
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How do I solve for x in the following question? I'm pretty sure you have to factor, but how do I solve for x with two x variables?

4x^2 + x = 0
 
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'x' is a common factor to both terms. Factor it out:

x(4x + 1) = 0


Do you know how to solve it now?
 
Ummm I am not too sure
 
Lol.
4x^2 + x = 0
from there, you can take out the x.
so.. x(4x+1)=0 since (that is equilivent to 4x^2 + x = 0 )
so now, you have (x) times (4x+1) equals 0, what do either have to be in order for the equation to equal 0?
0!
so you have x=0 and 4x+1=0
you solve for x, and you get 0,-1/4
 
0 or -0.25 via the "quadratic formula".
 
EDIT: Yup I figured it out before I refreshed the page lol. Thanks guys.
 
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