How to solve general motion in a straight line problems

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Shah 72
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Printed textbook problem 7: a small stone is dropped into a lake, with s = 4t^2 - sqrt(2t^3) giving depth after t seconds; parts a and b ask to show it takes 2 s and find the depth.

I don't know how to calculate this. Pls help
 
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$s = 4t^2 - \sqrt{2t^3}$

have you learned any calculus, specifically derivatives?
 
skeeter said:
$s = 4t^2 - \sqrt{2t^3}$

have you learned any calculus, specifically derivatives?
Yeah so ds/dt=8t-3sqroot(2t)/2
 
skeeter said:
$s = 4t^2 - \sqrt{2t^3}$

have you learned any calculus, specifically derivatives?
I have tried doing this so ds/dt=v
13= 8t-3sqroot (2t)/2
 
skeeter said:
$s = 4t^2 - \sqrt{2t^3}$

have you learned any calculus, specifically derivatives?
So I get quadratic equation. I got t=2s. Thank you very much!