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Homework Help: How to solve the ODE ty' + 2y = 4t^2

  1. Aug 3, 2010 #1
    1. The problem statement, all variables and given/known data
    Hi all, I'm trying to solve an ordinary differential equation. The problem is ty' + 2y = 4t^2


    2. Relevant equations



    3. The attempt at a solution

    I got down to [tex]\int (t^{2})\frac{dy}{dt}[/tex] + [tex]\int 2ty[/tex] = [tex]\int 4t^{3}[/tex]

    I am not sure about how to integrate the left side of the equation. The dy/dt make y make the problem confusing.

    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Aug 3, 2010 #2
    Re: Ode

    just recognize
    [itex] t^2 y' + 2 t y = (t^2 y)' [/itex]
    and use the fundamental theorem to say
    [itex] \int f'(t) dt = f + C [/itex].
     
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