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P= density (water) * head (meters) * flow rate (cubic meter per second) * g * efficiency

I understand how to plug in everything except for the flow rate variable. I would like to get help in deriving 2 things for the following set up: If I have a reservoir that is 20m by 20m by 20m (8000 cubic meters of water) and it is 70 meters high.

1. How big would my pen stock tunnel diameter half to be achieve a 50 cubic meter per second drop? Or is that a function of the head size and the diameter?

2. If I achieved the 50 cubic meter per second...would the reservoir empty out in about 160 seconds? (8000 cubic meter / 50 seconds??)