How to Use the Method of Undetermined Coefficients for Differential Equations?

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The discussion focuses on setting up the particular solution for the differential equation y'' + 25y = -1x cos(5x) using the Method of Undetermined Coefficients. The proposed form for the particular solution is A*x^2*cos(5x) + B*x^2*sin(5x) + C*x*cos(5x) + D*x*sin(5x) due to the presence of cos(5x) and sin(5x) in the homogeneous solution. This adjustment is necessary because the standard forms for undetermined coefficients must be modified when the terms are solutions to the homogeneous equation. The participants clarify the need to multiply by x to avoid duplication with the homogeneous solutions. Understanding these adjustments is crucial for correctly setting up the particular solution.
Tom McCurdy
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Homework Statement



Set up but do not solve for the appropriate particular solution yp for the differential equation

y''+25y=–1xcos(5x)

using the Method of Undetermined Coefficients (primes indicate derivatives with respect to x).

In your answer, give undetermined coefficients as A, B, etc.

Homework Equations


Possible Derivatives
  • sin(x)
  • cos(x)
  • xsin(x)
  • xcos(x)



The Attempt at a Solution



This seems like the solution should simply be

A*x*sin(5*x)+B*x*cos(5*x)+C*cos(5*x)+D*sin(5*x)
 
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What solution are you talking about? The problem said "Set up but do not solve for the appropriate particular solution yp for the differential equation
y''+25y=–1xcos(5x)
using the Method of Undetermined Coefficients"

Normally, to get a solution of the form "x cos(5x)" you would use (Ax+B) cos(5x)+ (Cx+ D) sin(5x). However, in this case cos(5x) and sin(5x) are solutions to the homogeneous equation. Multiply what you would normally use by x: (Ax2+ Bx)cos(5x)+ (Cx2+ Dx)sin(5x).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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