How would a radial component of induced electric field makes flux ≠ 0

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    Induced electric field
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SUMMARY

The discussion centers on the concept of electric flux in relation to a radial component of the induced electric field, as described in "Resnick, Halliday, and Krane." When a uniform magnetic field is present, and a cylindrical Gaussian surface is considered, the symmetry of the electric field ensures that the flux through the surface is non-zero. The integral of the electric field over the surface, represented as ##\vec E\cdot d\vec S##, remains constant due to the uniform direction of the electric field, confirming that the net electric flux is indeed not zero.

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KnightTheConqueror
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I don't understand this paragraph of Resnick halliday Krane where it says that if a radial component of induced electric field exists, it would mean net electric flux is not zero. I guess I am not exactly able to visualise the gaussian surface and how the flux is not zero. Please help
 

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You appear to have a uniform magnetic field pointing out of the page. The Gaussian surface being considered is any arbitrary cylindrical surface with its axis pointing out of the page. The symmetry of the situation under rotation about the axis of our arbitrary cylinder means that if the electric field points outwards at any point on the surface it points outwards everywhere on the surface, so ##\vec E\cdot d\vec S## has the same value everywhere and hence the integral is necessarily non-zero.

Other symmetry arguments are available under these circumstances, but that seems to be the one they picked, if I understand right.
 
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Thank you. After reading your answer I read the paragraph in the book again and now everything is clear
 
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