How would I find the magnitude of this wave.(complex numbers/quanties)

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The discussion focuses on calculating the magnitude of the wave function ψ(y,t) = 2e^(iky)e^(iωt) + 4e^(iky)e^(-iωt). The user simplifies the expression to 2e^(iky)(3cos(ωt) - isin(ωt)) and seeks guidance on determining its absolute value. The correct approach involves rewriting the wave function to highlight its sinusoidal components, leading to the realization that the magnitude depends on time. Ultimately, the user concludes that the magnitude is expressed as √(20 + 16cos(ωt)).

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ψ(y,t)=2*e^(iky)*e^(iωt) + 4*e^(iky)*e^(-iωt)
Here is my work for the problem
2e^(iky)*(e^(iωt)+2e^(-iωt)); 2e^(iky)*(cos(ωt)+i*sin(ωt)+2cos(ωt)-2i*sin(ωt));
2e^(iky)*(3cos(ωt)-isin(ωt))
How would you continue this problem?
 
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You are asked for the absolute value (or magnitude) of 2e^{iky}(3\cos(\omega t)-i\sin(\omega t)).
I'm sure you know how to calculate the magnitude of a complex number.
The magnitude will depend on time.
 
My advice would be to rewrite the wave in the form:

\Psi(y,t) = 2e^{i(ky + \omega t)} + 4e^{i(ky - \omega t)}

and it should be obvious from this form that you have the sum of two sinusoidal waves, one traveling to the left (er, negative y-direction) with amplitude 2, and the other to the right (+ y-direction) with amplitude 4. If that is not obvious, then consider that if this is really a physical wave propagating along the y-axis, then the physical wave is given by:

Re[\Psi(y,t)] = 2\cos{(ky + \omega t)} + 4\cos{(ky - \omega t)}

To be honest, I'm not sure how/don't feel like putting in the effort at this hour to calculate the combined amplitude of the two waves, and whether that corresponds to the magnitude of the complex number psi.

Edit, just saw Galileo's post, so maybe I was way off on this one/answering the wrong question.
 
How do you edit posts?
Anyway I end up getting (20+16cos(wt))^1/2 for my magnitude.
 
The magnitude of 2e^{iky}(3\cos(\omega t)-i\sin(\omega t)) is not \sqrt{20+16\cos(\omega t)}.
Try again.

Click the edit button at the bottom of your post to edit.
 

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