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## Homework Statement

How would you find the anti derivative of (1+x^2)^(1/2)

I am trying to find the definite integral of that function from 0 to 1

## Homework Equations

## The Attempt at a Solution

Here is what I tried so far: I let u=1+x^2

du=2xdx

solving for dx, dx=(1/2x)du

I plug dx into the integral to get

(integral sign)(1/(2x))(u)^(1/2)du

So after I solve this I get [(1+x^2)^(3/2)]/(3x) from 0 to 1. But obviously this is wrong because if I plug 0 in for x, the function does not exist!