How would you find the anti derivative of (1+x^2)^(1/2)
I am trying to find the definite integral of that function from 0 to 1
The Attempt at a Solution
Here is what I tried so far: I let u=1+x^2
solving for dx, dx=(1/2x)du
I plug dx into the integral to get
So after I solve this I get [(1+x^2)^(3/2)]/(3x) from 0 to 1. But obviously this is wrong because if I plug 0 in for x, the function does not exist!