Hybridization of atoms in heterocyclic compounds

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SUMMARY

The discussion centers on the hybridization of atoms in heterocyclic compounds, specifically focusing on aromaticity. It is established that all atoms in an aromatic compound must be sp2 hybridized, including heteroatoms like nitrogen, oxygen, and sulfur, which can exhibit sp2 hybridization when conjugated to a pi-bond. The conversation highlights that hybridization is a conceptual tool from Valence Bond Theory, while pi bonding stems from Molecular Orbital Theory. Ultimately, the hybridization state is a matter of convention rather than a strict physical reality, as the coordination of the atom is more critical for understanding its role in delocalized bonding and aromatic structures.

PREREQUISITES
  • Understanding of aromaticity in organic chemistry
  • Familiarity with Valence Bond Theory
  • Knowledge of Molecular Orbital Theory
  • Basic concepts of hybridization (sp2 and sp3)
NEXT STEPS
  • Research the role of heteroatoms in aromatic compounds
  • Study the differences between Valence Bond Theory and Molecular Orbital Theory
  • Explore the concept of delocalized bonding in organic molecules
  • Learn about the coordination geometries of heteroatoms in various compounds
USEFUL FOR

Chemists, organic chemistry students, and researchers focusing on heterocyclic compounds and aromaticity will benefit from this discussion.

Mayhem
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TL;DR
How to determine whether a non-carbon in a heterocyclic compound is sp, sp2, or sp3 hybridized.
I'm trying to fortify my understanding of aromaticity in heterocyclic compounds. I understand that every atom in an aromatic compound must be sp2 hybridized (I don't like the "conjugated" definition), which is easy to spot for carbon, but how do I determine it for atoms such as nitrogen, oxygen, sulfur and so on?
 
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I looked into it some more, and it seems that my confusion arose from the fact that seemingly sp3 hybridized nitrogen atoms can be sp2 hybridized if they are conjugated to a pi-bond. Apparently it's energetically more favorable to assume sp2 geometry in this situation. This explains why something like pyrrole is indeed aromatic.
 
The atoms "are" not hybridized. It is you who decides to use one or the other hybridization to better describe the electronic wavefunction. For example, you can assume carbon to be sp3 hybridized or sp2 hybridized in ethylene and obtain almost the same binding energy and atomic distances. Also note that hybridization is a concept from Valence bond theory, while pi bonding is from molecular orbital theory. So the question is what you really learn from ascribing a hybridization tag to an atom? Usually it would be sufficient to specify the coordination of the atom (planar trigonal vs trigonal pyramidal) and not to talk about hybridization at all.
 
DrDu said:
The atoms "are" not hybridized. It is you who decides to use one or the other hybridization to better describe the electronic wavefunction. For example, you can assume carbon to be sp3 hybridized or sp2 hybridized in ethylene and obtain almost the same binding energy and atomic distances. Also note that hybridization is a concept from Valence bond theory, while pi bonding is from molecular orbital theory. So the question is what you really learn from ascribing a hybridization tag to an atom? Usually it would be sufficient to specify the coordination of the atom (planar trigonal vs trigonal pyramidal) and not to talk about hybridization at all.
Yes, but in what direction is it defined? Does hybridization define coordination or the other way around?
 
Neither
 
DrDu said:
Neither
Then what?
 
As I said, you can describe an atom in a given compound with different hybridizations. In the case of nitrogen, it is not even necessary to assume it hybridized at all. To describe planar coordinations with sp2 and ##\psi## tetraheldral ones with sp3 is mostly convention and not physical reality. As a chemist, you will have to know the coordination of the heteroatom and may from this deduce whether, it may participate in a delocalized bonding or aromatic structure. If you describe the corresponding structure with un-hybridized, sp2 or sp3 hybridized atoms won't make any difference to the properties you observe.
 

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