Hybridized orbitals (can't understand diagram)

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Discussion Overview

The discussion revolves around the hybridization of orbitals in boron (B), specifically addressing the electronic configuration and the interpretation of notation involving noble gas configurations. Participants explore the implications of hybridization, the existence of orbitals, and the role of the 1s subshell in this context.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants question why there are two 2p orbitals in boron, given its electronic configuration of 1s2 2s2 2p1.
  • Others clarify that orbitals exist regardless of whether they are occupied, suggesting that the presence of empty orbitals is relevant to hybridization.
  • There is a discussion about the notation [He], with some participants explaining it as a shorthand for the electronic configuration of helium, indicating that it simplifies writing configurations for larger atoms.
  • Some participants express confusion about whether helium is involved in the hybridization process or if it merely represents the configuration of boron.
  • Concerns are raised about the energy levels of hybrid orbitals compared to the original 2s and 2p orbitals, with inquiries into whether hybrid orbitals have lower energy than 2p orbitals and higher than 2s orbitals.
  • Participants note that the 1s subshell is closed and does not participate in hybridization due to a significant energy gap, although it is acknowledged that it exists in boron.
  • There is a debate about the existence of subshells in boron, with some asserting that all possible subshells exist even if they are not occupied in the ground state.

Areas of Agreement / Disagreement

Participants express differing views on the role of the 1s subshell in hybridization and the interpretation of the electronic configuration notation. There is no consensus on the implications of these points, and several questions remain unresolved.

Contextual Notes

Some participants highlight that empty orbitals do not hybridize, and there is an ongoing discussion about the energy levels of hybrid orbitals versus original orbitals. The complexity of hybridization in relation to electronic configurations is also noted.

coconut62
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Please see attachment.

1. "Now the 2s orbital and two of the 2p orbitals of B hybridize to form a set of three equivalent sp2 hybrid orbitals." The notes says.

Can someone tell me why are there two 2p orbitals in B? I thought electronic configuration of B is 1s2 2s2 2p1?

2. What does the [He] beside B mean?

Thanks in advance.
 

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coconut62 said:
Can someone tell me why are there two 2p orbitals in B? I thought electronic configuration of B is 1s2 2s2 2p1?

Orbitas - as a place for an electron - exist regardless of whether they are occupied or not.

What does the [He] beside B mean?

It is a shortcut notation - replace [He] with configuration of the noble gas.
 
Why is Helium needed? Is it the Boron itself hybridizes or it hybridizes together with He?
 
coconut62 said:
Why is Helium needed? Is it the Boron itself hybridizes or it hybridizes together with He?

Helium is not needed, the notation simply means the electronic configuration of He.

So, instead of 1s2 2s2 2p1; as He is 1s2 you can write it as [He] 2s2 2p1. May not be so much of an advantage here, but in larger atoms like e.g. Gold, or Iodine having to write out lots of terms each time is prone to error.
 
Think about cesium. [Xe] 6s1 looks much more neat than 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s1, doesn't it? And they mean exactly the same.
 
So the [He] is actually together with the dotted square, not the B on the left?

And is the energy level of the hybrid orbitals lower than the 2p's? And higher than the 2s?
 
coconut62 said:
So the [He] is actually together with the dotted square, not the B on the left?

You can put it that way.
 
How about its energy level?
 
B has three 2p orbitals. And one 2s.
Empty orbital doesn't hybridize.
 
  • #10
ycheff said:
B has three 2p orbitals. And one 2s.
Empty orbital doesn't hybridize.

Where is its 1s?
 
  • #11
1s2 - (or [He]) - closed shell.
It can't hybridize. Too much energy gap between 1s and 2s.
 
  • #12
So you're saying that a B atom never has a 1s subshell? Even when it is an independent atom and not bonded to others?
 
  • #13
No, he says that 1s2 exists, but doesn't matter when talking about hybrydization and can be safely ignored. But I agree that the original statement was lousy to say the least.
 
  • #14
How come boron has so many subshells when it has only five electrons?

1s2 2s2 2p1 no?

is the 1s2 empty?
 
  • #15
Technically all possible subshells always exist, they are just not occupied in the unexcited atom.
 

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