Hydraulic Pump and Motor for Replacing 16HP Gas Engine

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SUMMARY

This discussion focuses on replacing a 16 horsepower gas engine with a hydraulic pump and motor system to drive a snowblower at 1000 RPM. The required torque for the snowblower is calculated to be 1008 in.lb using the formula Power = Torque X RPM / 63025. Key equations for determining the hydraulic pump's GPM and PSI are provided, emphasizing the need for efficiency calculations, specifically assuming 0.85 efficiency. The formulas for power and torque conversions are also outlined, ensuring that the hydraulic system maintains power conservation throughout.

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  • Understanding of hydraulic systems and components
  • Familiarity with torque and RPM calculations
  • Knowledge of efficiency metrics in hydraulic applications
  • Basic grasp of power conversion between horsepower and watts
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  • Research hydraulic pump sizing and selection criteria
  • Learn about hydraulic motor specifications and performance metrics
  • Explore efficiency optimization techniques for hydraulic systems
  • Study the impact of operating pressure on hydraulic performance
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This discussion is beneficial for mechanical engineers, hydraulic system designers, and technicians involved in replacing gas engines with hydraulic systems in applications like snowblowers.

lugnut
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need a hydraulic pump (gpm) ? to drive a hydraulic motor (torque)? - that has to replace a 16 horsepower gas engine - to drive a snowblower at 1000 rpm,s what is the formula for this? pump would be driven at arpox 3,000 rpm
 
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The power from the pump, the hydraulic motor, the snowblower and the driving motor/engine must all be the same (taking into account their respective efficiencies). Power is conserve throughout the system.

Equations and calculators available http://www.surpluscenter.com/Hydraulic.htm" .

Torque needed by the 16 hp snowblower @ 1000 rpm is 1008 in.lb (Power = Torque X RPM / 63025).

Assuming 0.85 efficiency, the characteristics of the motor are (you need to know the operating pressure or the GPM):

GPM = Torque X RPM / PSI X 2 X pi / 231 / 0.85

GPM and PSI will be the same for the pump. Power and torque for the pump are (assuming 0.85 efficiency):

Power = PSI X GPM / 1714 / 0.85 --> according to the website: «HP is for electric motors, double this for gas engines.» Multiply by 746 to convert into Watt (electric motor).

Torque (ft.lb) = 5252 X Power / RPM

Displacement of the pump and motor (with their respective RPM):

Displacement (in³/rev) = GPM X 231 / RPM
 
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