Hydrogen molecule as a harmonic oscillator

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SUMMARY

The discussion centers on modeling the covalent bond in the H2 molecule as a harmonic oscillator with a spring constant of k = 1100 N/m. The zero point energy (E0) was correctly calculated as E0 = 6.047 x 10^-20 J. However, the energy of the first excited state (E1) was incorrectly calculated as E1 = 1.814 x 10^-19 J, leading to confusion regarding the application of the quantum harmonic oscillator formula. The correct approach involves ensuring accurate values for the angular frequency (ω) and the quantum number (n).

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Homework Statement


The covalent bond between the two protons in the H2 molecule can be modeled by a harmonic spring with a spring constant k = 1100 N/m.

a. What is the zero point energy of the H2 molecule as a harmonic oscillator?

b. What is the energy of the first excited state?

m_{p}=1.6726*10^-27 kg

k=1100N/m

Homework Equations


m=\frac{m_{p}}{2}

\omega=\sqrt{\frac{k}{m}

E=(n+\frac{1}{2})\hbar\omega

The Attempt at a Solution



\omega=\sqrt{\frac{1200}{8.363*10^-28}

a. E_{0}=\frac{1}{2}\hbar\omega=6.047J*10^-20J this is CORRECT

b. ??E_{1}=\frac{3}{2}\hbar\omega=1.814*10^-19J ?? this is INCORRECT

i don't understand why b. is incorrect but a. is correct. i thought the only difference would be the number for n. what am i doing wrong? can anyone help please?
 
Last edited:
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Try using /tex instead of \tex in [\tex].
 
Astronuc said:
Try using /tex instead of \tex in [\tex].

thanks. i don't use that coding often. it should all be fixed now
 

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