What is the hydrostatic force on one end of an aquarium filled with water?

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The discussion revolves around calculating the hydrostatic force on one end of an aquarium filled with water. The aquarium dimensions are 8 m long, 4 m wide, and 4 m deep. The main confusion lies in interpreting "end" as either a side wall or half of the aquarium. The pressure varies with depth, leading to the realization that the force on the wall must be calculated by considering the pressure at different depths, which can be approached using integration. This highlights the need to sum the varying pressures across the height of the wall to find the total hydrostatic force accurately.
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Homework Statement



An aquarium `8` m long, `4` m wide, and `4` m deep is full of water. Find the following: the hydrostatic force on one end of the aquarium.

Homework Equations





The Attempt at a Solution



I already found the pressure and force on the bottom of the aquarium...now, my main issue understanding what the question means when it says 'end.' Do they mean one of the side walls? One half of the aquarium? If anyone happens to know what that likely means, that'd be awesome.

What I've tried so far is Density*gravity*L/2*W, which was wrong.

1000*9.8*4*4 = 156800.

Is it just the force on the bottom of the aquarium divided by 2? That almost seems too easy...
 
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IF the force is a constant, then the pressure on a surface is just that force times the area of the surface. That, I presume, was how you found the force on the bottom. However, the force, at each point on a wall, is not a constant. It varies with depth. Imagine a thin horizontal line, of width "dx", at depth "x". What is the force at depth x meters below the surface of the water? What is the pressure on that line? (For a very thin horizontal line you may assume the force is (approximately) a constant.) The total pressure on the wall is the sum of the pressure on all those lines. Doesn't that look like a "Riemann sum" to you? You can make it exact by converting the sum into an integral. (I have this suspicion that this problem is in a section on "applications of integrals".)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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