Hyperbolic Cosine curve fitting

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SUMMARY

The discussion centers on fitting a hyperbolic cosine curve to a hyperbola defined by the vertex at (0,0) and a point at (4,7). The relevant equation is y = a cosh(x/a) - a, where 'a' is a constant that shapes the curve. Attempts to solve for 'a' using algebra and Wolfram Alpha revealed no integer solutions, indicating the need for graphical methods. The conclusion emphasizes that the equation describes a catenary rather than a hyperbola, and suggests using graphing techniques to find the appropriate value of 'a'.

PREREQUISITES
  • Understanding of hyperbolic functions, specifically cosh
  • Familiarity with curve fitting techniques
  • Basic algebra and equation solving skills
  • Experience with graphing software or tools like Wolfram Alpha
NEXT STEPS
  • Learn how to graph hyperbolic functions using tools like Desmos or GeoGebra
  • Study the properties of catenary curves and their applications
  • Explore numerical methods for solving equations without closed-form solutions
  • Investigate the differences between hyperbolas and catenaries in mathematical contexts
USEFUL FOR

Students and educators in mathematics, particularly those focused on calculus, curve fitting, and hyperbolic functions. Additionally, anyone interested in the practical applications of mathematical modeling will find this discussion beneficial.

Denyven
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Homework Statement


I need to fit a curve using cosh to a hyperbola with a vertex of (0,0) and a point at (4,7).

The scanned worksheet can be found here
http://img519.imageshack.us/i/scan0001gu.jpg/"
http://img192.imageshack.us/i/scan0002uz.jpg/"

Homework Equations


y=a cosh (\frac{x}{a})-a=\frac{a}{2}(e^{\frac{x}{a}}+e^{\frac{-x}{a}})-a "is the formula for a hyperbola at a vertex of 0,0. a is a constant that modifies the shape" that is what the assignment said exactaly

The Attempt at a Solution


I plugged in 4 for x and 7 for y and attempted to solve algebraically, I just got stuck. then I plugged the equation I attempted to solve into wolfram alpha and got the response no integer solution.

http://www.wolframalpha.com/input/?i=7%3D(a/2)(e^(4/a)%2Be^(-4/a))%2Ba+solve+for+a
 
Last edited by a moderator:
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The solution value of a isn't an integer.

Try graphing the function

<br /> y=x cosh (\frac{4}{x})-x-7<br />

and use that to help you find the right value of a.
 
There is probably no closed-form solution, and besides, this formula doesn't describe a hyperbola, but a catenary.
 
hgfalling said:
The solution value of a isn't an integer.

Try graphing the function

<br /> y=x cosh (\frac{4}{x})-x-7<br />

and use that to help you find the right value of a.

Thanks so much for your help! I graphed that, and since you solved to equation for 0 then turned 0 into y I looked for the x intercept of the graph and the value fit, thank you so much!
But just for the sake of knowing, how can you guys tell if an equation has no closed form solution?
 
Last edited:

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