I am an idiot, me. (Find the force of a tennis ball)

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To find the net force acting on a 58-gram tennis ball that accelerates to 45 m/s over 44 cm, the relevant formula is F=ma. The acceleration due to the racket can be calculated using the final speed and distance, while gravity does not factor into this specific problem. The discussion emphasizes using kinetic energy and work done by the racket as an alternative approach. Participants suggest converting mass to kilograms and distance to meters before calculations. Ultimately, the net force is determined to be 130 N.
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This seems like such a pathetically elementary problem, and I feel like a total moron right now. Well, here it is:


When a 58 gram tennis ball is served, it accelerates from rest to a speed of 45 m/s. The impact of the racket gives the ball a constant acceleration over a distance of 44 cm. What is the magnitude of the net force acting on the ball?



The answer is 130 N. The only force formula I know is f=ma. I know that the distance (44 cm) is supposed to be used, and maybe gravity (9.8 m/s2) should be considered but I have no clue how. Thanks for any help :(
 
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Blablablabla said:
This seems like such a pathetically elementary problem, and I feel like a total moron right now. Well, here it is:

When a 58 gram tennis ball is served, it accelerates from rest to a speed of 45 m/s. The impact of the racket gives the ball a constant acceleration over a distance of 44 cm. What is the magnitude of the net force acting on the ball?

The answer is 130 N. The only force formula I know is f=ma. I know that the distance (44 cm) is supposed to be used, and maybe gravity (9.8 m/s2) should be considered but I have no clue how. Thanks for any help :(
Why would acceleration of gravity have anything to do with this? It doesn't.

Do you know how the work done on an object is related to the object's change in kinetic energy?
 
SammyS's suggestion that you look at the change in energy, the work done by the racket, is probably the simplest way to do this.

However, since you say "The only force formula I know is f=ma", you can do it that way. With a constant acceleration, a, and initial speed 0, the speed after the acceleration is v= at and the total distance moved would be (1/2)at^2. You know, then, that at= 45 m/s and (1/2)at^2= .44 m. You can solve the first equation for t in terms of a and then put that into the second equation to get an equation in the single variable a. After you know a, you can use "f= ma".
 
Before you do any of that, convert your mass to kg and your distance to meters.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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