Solving Tennis Physics: Force & Acceleration

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Homework Help Overview

The discussion revolves around a physics problem involving the forces and accelerations experienced by a tennis ball and racket during a collision. The original poster presents a scenario where a tennis racket strikes a tennis ball, prompting questions about the resulting accelerations and forces involved.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculations of acceleration and force, with some questioning the original poster's approach and unit conversions. There are mentions of momentum and its relevance to the problem, indicating a deeper exploration of the underlying physics principles.

Discussion Status

The conversation is ongoing, with participants providing guidance on unit conversions and raising questions about the application of momentum concepts. There is a mix of interpretations regarding the problem's requirements, and no consensus has been reached yet.

Contextual Notes

Some participants note that the original poster's physics class has not covered momentum yet, which may affect their understanding of the problem. There is also a focus on ensuring correct unit usage in calculations.

Meowserkitty
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Homework Statement



A tennis racket (950 g) hits a tennis ball (110 g) with a force of 5000 N. What is the acceleration of the tennis ball? During the collision, with what force does the tennis ball hit the tennis racket? What is the acceleration of the tennis racket? (Remember that force and acceleration are vectors, so be careful with positive and negative signs. Assume the player let's go of the racket just after contact.)

Homework Equations




f = m*a

The Attempt at a Solution


5000=110a
a) 45.4 m/s2
b) -5000 N
c) 5000=950a
-5.3 m/s2
 
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Hi Meowserkitty
Be careful with your units, 1N=1Kg/s²
 
oli4 said:
Hi Meowserkitty
Be careful with your units, 1N=1Kg/s²

Nope, 1N=(1kg(m))/s2
Also, whenever you see collisons, that just begs momentum. (p=mv)
Your answer was way too simplistic. Physics is (almost) never that easy, unfortunately.
 
Ah yes, sorry I forgot the m because I was looking at putting the bold tag around Kg first :)
 
Could you explain how I should go about this? Our physics teacher was gone all week and could not help us.
 
You just have to transform the mass expressed in g as expressed in Kg, that is, you divide it by 1000 :)
 
oli4 said:
You just have to transform the mass expressed in g as expressed in Kg, that is, you divide it by 1000 :)
Other than that do I do the same thing I did? And would the rackets acceleration be negative?
 
runningninja said:
Nope, 1N=(1kg(m))/s2
Also, whenever you see collisons, that just begs momentum. (p=mv)
Your answer was way too simplistic. Physics is (almost) never that easy, unfortunately.

We are not doing momentum yet
 
Meowserkitty said:
We are not doing momentum yet
Yes, you are :)
Maybe you didn't call it this way in class, but the Newton's law you are using is
"the force is the rate of change of momentum"
F=d(mv)/dt
As far as you are/will be concerned for a while, mass is constant, so that becomes
F=mdv/dt=ma :)
 

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