1. The problem statement, all variables and given/known data a car travels along a straight path at a constant speed of 60mi/h for a distance d and then another distance d in the same direction at another constant speed the average velocity over the entire trip is 30mi/h what is the constant speed with which the car moved during the second distance d 2. Relevant equations 3. The attempt at a solution v + 60mi/h = 30mi/h v = -30mi/h? this is really confusing me and here is why i know that instantaneous velocity is equal to average velocity for a particle under constant velocity but over the entire trip there is not a constant speed where the car moved 2d distance , because there in fact was a change in velocity(obviously) so i am really confused what do do here? do i simply just do vector addition?