I applying the difference/power rule (derivatives)

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Homework Help Overview

The problem involves taking the derivative of the expression (x - a), where 'a' is a constant. The subject area pertains to calculus, specifically the rules for differentiation.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the discrepancy between their reasoning and the solutions provided by their manual and Wolfram Alpha. They express confusion regarding the derivative of a constant and the application of the power and difference rules.

Discussion Status

Participants are providing clarifications regarding the nature of constants in differentiation. Some suggest applying the power rule and visualizing the function graphically to aid understanding. There is an exploration of different interpretations of the problem, but no explicit consensus has been reached.

Contextual Notes

There is a mention of the original poster's confusion stemming from the assumption that both variables are treated similarly, which raises questions about the treatment of constants in differentiation.

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Homework Statement



The problem is : take the derivative of (x - a)

Homework Equations



Power Rule : f '(x) = r x^(r-1)

Difference Rule : f '(x) = g '(x) - h '(x)

The Attempt at a Solution



This is such a simple problem but I don't understand how my solutions manual and Wolfram Alpha came to the answer. According to these sources the answer is 1.

However, because both variables in the expression are to a single power I was under the impression the derivative of each variable would equal 1, leading to (1 - 1) = 0

If you need any clarification, please let me know.
 
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The parameter 'a' represents a constant, not a variable. What's the derivative of a constant?
 
Keep in mind, x = x^1, so you can apply the power rule for this.
 
If it helps, try to graph the function in your head. For instance if you have a constant, \beta, which is a straight line intersecting the y-axis. Then it becomes clear that taking the derivative or finding another function that gives the slope at each point along \beta would definitely be 0 because a horizontal line has no slope.
 

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