I can't make sense of this log property explanation?

Click For Summary

Homework Help Overview

The discussion revolves around two distinct mathematical problems: the properties of logarithms and the plotting of a piecewise function. The first problem involves the relationship between logarithms of different bases, while the second focuses on graphing a quadratic function within specified intervals.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the algebraic manipulation of logarithmic identities and question the validity of the steps taken. They also discuss the interpretation of a piecewise function and the accuracy of plotted points in relation to the function's definition.

Discussion Status

Some participants have provided clarifications regarding the logarithmic properties and the piecewise nature of the function. There is ongoing exploration of the points plotted on the graph and their correspondence to the defined equations, with no clear consensus reached yet.

Contextual Notes

Participants are navigating potential misunderstandings regarding the definitions and representations of logarithmic functions and piecewise equations. The original poster expresses confusion about the algebraic proof and the graphing process, indicating a need for further clarification.

roger12
Messages
12
Reaction score
0

Homework Statement



I decided to cram these two unrelated question into one post, because they are too small and I don't want to crowd the forum with my many little bitty questions.


1. log(base A) of B= 1/[log(base B) of A]

because: if log(base B) of A=C, then B^C=A and so B=A^1/C

Hence, log(base A) of B= 1/C= 1/[log(base B) of A]

2. plot the graph of:

x^2+x+1: x<1, x=1 for [-3, 4] with intervals of 0.5

It's a part of a bigger graph.


Homework Equations





The Attempt at a Solution



1. I don't see how introducing C as equal to a different base and then carrying out a bunch of algebraic manipulations prove anything. Am I missing something here? Thank You.

2. x,y pairs (-3, 7), (-2, 3), (-1,1) I chose the whole numbers for x, because they are more convenient to me. If you look at this part of the graph in my book it goes through different points. Can, you please tell me where I went wrong? Thanks.
 
Physics news on Phys.org
roger12 said:
1. log(base A) of B= 1/[log(base B) of A]

because: if log(base B) of A=C, then B^C=A...
Remember the for logarithms,
logn x = y iff ny = x

So, using this, if
logB A = C, then BC = A.

... and so B=A^1/C
From
BC = A,
raise both sides to the exponent of 1/C, so
(BC)1/C = (A)1/C,
or B = A1/C.

... Hence, log(base A) of B= 1/C= 1/[log(base B) of A]

Using that definition of logarithms I gave earlier, Since
B = A1/C,
logAB = 1/C.

Substitute logB A = C into the fraction, so
logAB = 1/(logB A)
 
roger12 said:

Homework Statement



2. plot the graph of:

x^2+x+1: x<1, x=1 for [-3, 4] with intervals of 0.5

It's a part of a bigger graph.

The Attempt at a Solution


2. x,y pairs (-3, 7), (-2, 3), (-1,1) I chose the whole numbers for x, because they are more convenient to me. If you look at this part of the graph in my book it goes through different points. Can, you please tell me where I went wrong? Thanks.

Apparently you are graphing the equation y = x2 + x + 1, although what you showed is not an equation.

What does this part (in red) mean?
x^2+x+1: x<1, x=1[/color] for [-3, 4] with intervals of 0.5

The points you show, (-3, 7), (-2, 3), (-1,1), are on the graph of y = x2 + x + 1. Does the graph in your book come from this equation?
 
eumyang said:
Using that definition of logarithms I gave earlier, Since
B = A1/C,
logAB = 1/C.

Substitute logB A = C into the fraction, so
logAB = 1/(logB A)

Awesome! Why I forgot "If A=B^C, then C=log(base B)A" is beyond me.
 
Mark44 said:
Apparently you are graphing the equation y = x2 + x + 1, although what you showed is not an equation.

What does this part (in red) mean?


The points you show, (-3, 7), (-2, 3), (-1,1), are on the graph of y = x2 + x + 1. Does the graph in your book come from this equation?

The parts in red mean x is less than or equal to 1.

And it IS an equation :

y=x^2+x+1: x< or =1

and

y= 3-x : x>1

for [-3, 4]

y is defined differently for different values of x. But both expressions are the parts of the same equation. The part of the graph defined by y= 3-x : x>1 for [-3, 4] looks right, but the other part defined by y=x^2+x+1: x< or =1 for [-3, 4] doesn't sit on the points made up of ordered pairs above.
 

Similar threads

Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
10
Views
3K
  • · Replies 19 ·
Replies
19
Views
3K
Replies
4
Views
2K