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 Homework Statement
 Calculate the heat Q_H that a Carnot heat pump can deliver to the reservoir with a temperature T_H. Temperature of lower reservoir (T_L) and work (W, W>0) are given
 Homework Equations

Equations come from Carnot refrigeration cycle
1. W=Q_HQ_L
2. K=Q_L/W
So first I transformed the equation no 2 like this:
$$Q_L=K\cdotW$$
And then I transformed the first equation to find ##Q_Z##
$$Q_L=Q_HW$$
Plugging the result into the first equation
$$Q_H=K\cdot W+W$$
$$Q_H=W\cdot (K+1)$$
We know that the efficiency coefficient K is greater than 0, so how is it possible that the energy "pumped" into the hot reservoir (##Q_H##) is greater than the work that was put into the system?
$$Q_L=K\cdotW$$
And then I transformed the first equation to find ##Q_Z##
$$Q_L=Q_HW$$
Plugging the result into the first equation
$$Q_H=K\cdot W+W$$
$$Q_H=W\cdot (K+1)$$
We know that the efficiency coefficient K is greater than 0, so how is it possible that the energy "pumped" into the hot reservoir (##Q_H##) is greater than the work that was put into the system?