I don't understand how I am "calculating for the voltage drop"

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The discussion revolves around understanding voltage drop in a circuit with a light-emitting diode (LED) and a resistor connected to a 9V battery. It clarifies that the voltage drop across the LED is 2V, leaving 7V to drop across the resistor, which is calculated using Ohm's Law. Participants emphasize that the resistor actively uses voltage, functioning as a current-limiting device, and that the voltage drop is not merely "left-over" voltage. The conversation also touches on the importance of checking the LED datasheet for the correct forward voltage (Vf) and current ratings to ensure proper operation. Overall, the discussion highlights the relationship between voltage, current, and resistance in electrical circuits.
  • #31
analogdesign said:
I get it. You're a pedant. I'm a sloppy engineer. Fine. I'm sorry you didn't sleep well last night.
I like to think that 'pedants' will be responsible for checking the aeroplane that I plan to fly in on Friday.
I can also be as sloppy as the next man, when conversing with colleagues - but, when I am trying to help someone to learn something that is new to them, I think I owe it to them to be as accurate as possible. That's only fair to them, I feel. Langauge is, as you say, defined by its use. But if terms are used inappropriately and their meanings are not defined and held in common, what happens to the communication? I would never carry on this way on a Ham Radio or Amateur Constructors' Forum but I thought PF had some standards.
Did you have any evidence about the term 'active' or are you too cross to give me any?
 
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  • #32
sophiecentaur said:
Did you have any evidence about the term 'active' or are you too cross to give me any?

I'm not cross. The issue here is you're not "more accurate" because there is no objective definition by a generally accepted body clearly defining the terms "passive" and "active" with respect to electronics. You pick a definition you like (often for sound reasons, then act like the definition came down from on high and was etched on stone thousands of years ago).

Many people, yourself included, subscribe to the definition that an active device has a power supply and a method of control.

Other people define active as a device that requires a source of power to operate. Often diodes require that. Sometimes they don't.

You have to set up an LED with a constant current to drive it. You can't just let the signal power it as a resistor or capacitor can (unless you've got a very unusual signal). To some sloppy people, that is considered an active device.

As I mentioned, I agree with you. Describing a diode as passive is probably more descriptive. But being so rigid in your thinking will just turn people off electronics as a hobby. Hell, it's turning me off from helping answer questions as a hobby.

Here are some examples of people describing diodes as active. The first one is a university. The second is wikipedia. The third is a tutorial from a company. The last is an MS thesis from MIT.

http://www.ami.ac.uk/courses/topics/0133_itc/
http://en.wikipedia.org/wiki/Electronic_component
http://sound.westhost.com/beginners.htm
http://dspace.mit.edu/bitstream/handle/1721.1/47505/40295442.pdf <-- calls PIN diodes active elements
 
  • #33
http://sound.westhost.com/beginners.htm

Actually that one lists them as passive ... but a special case

Passive: Capable of operating without an external power source.
Typical passive components are resistors, capacitors, inductors and diodes (although the latter are a special case).

personally I have been told and understood all semiconductor devices to be active

Passive was for resistors, capacitors, inductors

Dave
 
  • #34
davenn said:
http://sound.westhost.com/beginners.htm

Actually that one lists them as passive ... but a special case



personally I have been told and understood all semiconductor devices to be active

Passive was for resistors, capacitors, inductors

Dave

The old 'categorising' problem has reared its head again. If you try to put your finger on what exactly is 'active' then you need a definition and not just an arbitrary classification. If 'active' implies control of some parameter, by another (i.e. there has to be a source of power and an output which depends upon the value of an input quantity ) then where do you draw the line between a mixer diode and a full blown amplifier? If you are going to include all semiconductors in the category 'active' then the terms 'active' and 'non-linear' mean the same thing - which means the term is redundant.

If 'active' is taken to mean that a power supply (of some sort) is involved then, at least, there is less possibility of confusion. An 'active' loudspeaker system would not be expected to contain merely some diodes, for added distortion; we would assume there is a power supply somewhere, other than just the audio power form the amplifier.
otoh, a mixer diode (used as part of a larger circuit, of course) could be said to use the Power from a local oscillator to provide a frequency shifted version of an input signal. In that context, it could be active. But so could a piece of resistance wire where the current through it can be controlled by its temperature. It satisfies the condition of control of one quantity by another so it would have to b e an 'active' device.

You could lose a lot of sleep about this, if you were so inclined.
 
  • #35
I think the total voltage drop in the circuit is = to the supply voltage in a simple dc series circuit like this. The led has a certain resistance, as does the passive resistor. The voltage drop across each will be equal to V=I*R.

The current that is flowing in the circuit will be equal to I = V/R (where R is the total resistance in the circuit) The voltage drop across each resistance, is according to the resistance of of that part of the circuit, and the current flow will be the same in all parts of the curcuit. Maybe neglible in most circuitry is the fact that the wires or other conductors like circuit board traces also have some resistance to the current flow.
 
  • #36
Ohm's law is a law not a suggestion.

For semiconductor diodes and LED's though R is a function of both current and temperature, and maybe even incident light, so the arithmetic gets more complicated than for a simple ideal circuit element.
Opto devices excluded they're not active so much as they're simply nonlinear.

http://www.merriam-webster.com/dictionary/active
c of an electronic circuit element : capable of controlling voltages or currents
 
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