- #1

kentm

- 16

- 1

[tex]\begin{math}y=\sqrt{9-x^2}\end{math}[/tex]

I figured the proper integral for this would be:

[tex]\begin{math}4\int_0^3 \sqrt{9-x^2}\end{math}[/tex]

but then I realized I'm not fully equipped to take that anti derivative. Substitution never fully gets rid of the x, and I'm unaware of a standard anti derivative that could be used to calculate such an integral. How would you go about this?