I have a variable as an exponent, how do I isolate it from everything else?

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Homework Help Overview

The problem involves isolating a variable in an exponent within the equation .75 = 1 - (1 - p)^n, with the goal of expressing n in terms of p.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of logarithms as a method to isolate the variable n. Some suggest taking the logarithm of both sides of the equation to facilitate this process.

Discussion Status

There is an ongoing exploration of logarithmic properties and their application to the problem. Some participants have provided guidance on using logarithms to manipulate the equation, but no consensus on a complete solution has been reached.

Contextual Notes

Participants are working under the constraints of expressing n in terms of p without arriving at a final answer. The original poster expresses uncertainty about isolating n without retaining other numbers in the equation.

kelp
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Homework Statement


.75 = 1 - (1 - p)^n
I want to get the n alone, and find n in terms of p.


Homework Equations





The Attempt at a Solution


I simplified it to this:
1 - p = (.25)^(1/n)
Basically, I just moved numbers around. I do not know how to get the n by itself without dragging along a number.

Thanks!
 
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kelp said:

Homework Statement


.75 = 1 - (1 - p)^n
I want to get the n alone, and find n in terms of p.


Homework Equations





The Attempt at a Solution


I simplified it to this:
1 - p = (.25)^(1/n)
Basically, I just moved numbers around. I do not know how to get the n by itself without dragging along a number.

Thanks!
Take the log of both sides.

.75 = 1 - (1 - p)n
==> .25 = (1 - p)n
==> ln(.25) = ln[(1 - p)n]

Using one of the properties of logarithms, you can work with the right side to eventually isolate n.
 
Have you tried logarithms?
 
Logarithms would be the best way to get change the variable from a constant to a coefficient. Any logarithm will work, whether it be the standard log10, the natural log ln, or any other one.

Just keep in the back of your head that:

log(ax) = x*log(a)

Here's an example on how to use this property:

3.2x = 10.24
ln(3.2x) = ln(10.24)
Using the property mentioned:
x*ln(3.2) = ln(10.24)
x*1.1631 = 2.3263
x = 2.3263/1.1631
x = 2

Note (again) that it doesn't matter whether you choose the ln or log10 or log12345, so long as you use the logarithm on BOTH sides of the equation and then use the mentioned property you'll be fine.
 

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