- #1

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I think on the first part you take the sum F=0 I think

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- #1

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I think on the first part you take the sum F=0 I think

- #2

mezarashi

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The force summation in the direction of the length of the rope must be equal to F = v^2/r as he is undergoing circular motion. There are only two forces involved: rope tension and gravity.

- #3

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so will the angles made on the triangle be 45degrees? and I use them in my calculations?

- #4

mezarashi

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Where are you getting the 45 degrees from? Are you using trigonometry?

- #5

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- #6

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b)ohhh, I see what u mean by using the conservation of energy. So, it is mgh = 0.5mv^2 + mgh,

The force summation in the direction of the length of the rope must be equal to F = v^2/r as he is undergoing circular motion. There are only two forces involved: rope tension and gravity.

9.8 * 4 = 0.5 * v^2 + 9.8 * 1.5

v = 7m/s.

Plugging in the equation F = ma,

F = m * v^2 / r

F = 70kg * 7^2 / 4

F = 857N

So the answer is 857 N??? I think this number is too large...

For a, the answer should be 0, because when you plug in F = m * v^2/r, since v is 0, F would also be 0

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