I need help understanding the derivation of this 'Absolute Scale of Temperature'

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SUMMARY

The discussion centers on the derivation of the Absolute Scale of Temperature as presented in SL Arora's Class 11 textbook, specifically on page 11.3 under section 11.7. The key concept discussed is Charles's Law, which states that the volume (V) of a gas is directly proportional to its temperature (T) at constant pressure. The conversion to the Absolute Scale involves adding 273.15 to the Celsius temperature, resulting in the expression (T + 273.15) for temperature in Kelvin.

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Shauryafrom2006
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I can't figure out the derivation of this formula.
It is from [ Class 11th] SL Arora, pg no. 11.3, the heading is [11.7] Absolute Scale of Temperature.
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This is just Charles law (V/T is onstant at constant pressure), with T expressed in degrees Celsius, so you get (T+273.15) in the expression, instead of t
 
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Oh... I see, I get it now :)
 

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