I want to calculate mark space ratio: f=25000Hz,T=4us

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SUMMARY

The discussion focuses on calculating the mark-to-space ratio and mark-to-phase ratio for a signal with a frequency of 25,000 Hz. The mark time is determined to be 0.4 μs, while the space time is calculated as 3.6 μs, leading to a mark-to-space ratio of 1:9. The total period of the waveform is clarified as 40 μs, which is derived from the frequency. The participants seek clarification on the origin of the 4 μs value and the definition of the mark-to-phase ratio.

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engnrshyckh
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<Moderator's note: Moved from a technical forum and therefore no template, which would have helped a lot in this case ...>

i know that mark time is duration in which a pulse is present and space time is a duration is which pulse is not present. my attempt to ques is: f= 25000Hz...> t=1/f=0.4us which means pulse is present for 0.4us. that is mark time is .4us. space time 4-0.4=3.6us s therefore:
Mark:space= 0.4:3.6
=4:36,,,...>1:9 please tell me if i my calculation is faulty. Also what will be mark to Phase ratio
 
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The period of a complete cycle is the reciprocal of frequency.
 
Asymptotic said:
The period of a complete cycle is the reciprocal of frequency.
25000hz leads to 0.4us not 4us so something is missing :P
 
engnrshyckh said:
25000hz leads to 0.4us not 4us so something is missing :P

1/25 KHz = 1/25 ms. 1/25 ms = 0.04 ms.
0.04 ms = 40 μs total period.
Total time = Mark time + Space time

engnrshyckh said:
space time 4-0.4=3.6us
Where did the 4 μs value come from?

How is this "mark to phase ratio" defined? It's new terminology to me.
 
Asymptotic said:
1/25 KHz = 1/25 ms. 1/25 ms = 0.04 ms.
0.04 ms = 40 μs total period.
Total time = Mark time + Space timeWhere did the 4 μs value come from?

How is this "mark to phase ratio" defined? It's new terminology to me.
4us is given in question... if i simplify the question then i want to find mark to space and mark to phase ratio given the frequency and time period. i havnt either heard about the letter
 
If a single cycle of the waveform is 40 μs wide, and the mark time is 4 μs wide, then what is the duration of the 'space'?
 

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