*IBV5 The vectors u, v are given by u = 3i + 5j, v = i – 2j

  • Context: MHB 
  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Vectors
Click For Summary
SUMMARY

The discussion focuses on solving for scalars \(a\) and \(b\) in the vector equation \(a(u + v) = 8i + (b - 2)j\), where \(u = 3i + 5j\) and \(v = i - 2j\). The sum of the vectors \(u\) and \(v\) results in \(u + v = 4i + 3j\). By setting \(a = 2\), the equation simplifies to \(2(4i + 3j) = 8i + 6j\), leading to \(b = 8\) after solving \(3a = b - 2\). Thus, the final values are \(a = 2\) and \(b = 8\).

PREREQUISITES
  • Understanding of vector addition and representation in component form.
  • Knowledge of scalar multiplication in vector spaces.
  • Familiarity with solving linear equations.
  • Basic concepts of real and complex numbers in mathematics.
NEXT STEPS
  • Study vector operations in linear algebra, focusing on scalar multiplication.
  • Learn about vector spaces and their properties in mathematics.
  • Explore more complex vector equations and their solutions.
  • Investigate applications of vectors in physics and engineering contexts.
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with vector equations and require a solid understanding of scalar values in vector operations.

karush
Gold Member
MHB
Messages
3,240
Reaction score
5
The vectors $u, v$ are given by $u = 3i + 5j, v = i – 2j$
Find scalars $a, b$ such that $a(u + v) = 8i + (b – 2)j$

$(u+v)=4i+3j$
in order to get the $8i$ let $a=2$
then $2(4i+3j)=8i+6j$
in order to get $6j$ let $b=8$ then $(8-2)j=6j$
so $a=2$ and $b=8$

I am not sure of the precise definition of what scalar means here...at least with vectors
 
Physics news on Phys.org
vectors u,v are given by u=3i+5j,v=i–2j
Find scalars a,b such that a(u+v)=8i+(b–2)j

u + v = <4,3>

Then <4a,3a> = <8,(b-2)>

4a = 8

3a = b-2
 
karush said:
I am not sure of the precise definition of what scalar means here...at least with vectors
The definition is the same with everything; basically a number. Whether it's restricted to real or complex numbers is usually clear from context.
 
tkhunny said:
vectors u,v are given by u=3i+5j,v=i–2j
Find scalars a,b such that a(u+v)=8i+(b–2)j

u + v = <4,3>

Then <4a,3a> = <8,(b-2)>

4a = 8

3a = b-2

yes, that looks like a much better way to solve it. especially if it gets a lot more complicated.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 43 ·
2
Replies
43
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K