*IBV5 The vectors u, v are given by u = 3i + 5j, v = i – 2j

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Discussion Overview

The discussion revolves around finding scalars \(a\) and \(b\) such that the equation \(a(u + v) = 8i + (b - 2)j\) holds true, given the vectors \(u = 3i + 5j\) and \(v = i - 2j\). The scope includes mathematical reasoning and vector operations.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant calculates \(u + v\) as \(4i + 3j\) and proposes \(a = 2\) and \(b = 8\) based on the equation \(2(4i + 3j) = 8i + 6j\).
  • Another participant also derives \(u + v\) as \(\langle 4, 3 \rangle\) and sets up the equations \(4a = 8\) and \(3a = b - 2\) to find \(a\) and \(b\).
  • A participant expresses uncertainty about the definition of a scalar in the context of vectors, suggesting that it generally refers to a number.
  • A later reply agrees with the vector representation and the method used to solve for \(a\) and \(b\), indicating it may be more efficient for complex problems.

Areas of Agreement / Disagreement

Participants appear to agree on the method of solving for \(a\) and \(b\) using vector addition, but there is some uncertainty expressed regarding the definition of scalars.

Contextual Notes

There is a lack of clarity on the precise definition of scalars in this context, and the discussion does not resolve the potential ambiguity regarding whether scalars are restricted to real or complex numbers.

Who May Find This Useful

Readers interested in vector mathematics, particularly in the context of linear algebra and scalar multiplication, may find this discussion relevant.

karush
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The vectors $u, v$ are given by $u = 3i + 5j, v = i – 2j$
Find scalars $a, b$ such that $a(u + v) = 8i + (b – 2)j$

$(u+v)=4i+3j$
in order to get the $8i$ let $a=2$
then $2(4i+3j)=8i+6j$
in order to get $6j$ let $b=8$ then $(8-2)j=6j$
so $a=2$ and $b=8$

I am not sure of the precise definition of what scalar means here...at least with vectors
 
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vectors u,v are given by u=3i+5j,v=i–2j
Find scalars a,b such that a(u+v)=8i+(b–2)j

u + v = <4,3>

Then <4a,3a> = <8,(b-2)>

4a = 8

3a = b-2
 
karush said:
I am not sure of the precise definition of what scalar means here...at least with vectors
The definition is the same with everything; basically a number. Whether it's restricted to real or complex numbers is usually clear from context.
 
tkhunny said:
vectors u,v are given by u=3i+5j,v=i–2j
Find scalars a,b such that a(u+v)=8i+(b–2)j

u + v = <4,3>

Then <4a,3a> = <8,(b-2)>

4a = 8

3a = b-2

yes, that looks like a much better way to solve it. especially if it gets a lot more complicated.
 

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