Ideal Gas Compression Homework: T(cylinder) = 298K

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Homework Help Overview

The discussion revolves around a problem involving the compression of nitrogen gas in a cylinder at room temperature, specifically focusing on the temperature of gas escaping from the cylinder. The given parameters include the temperature of the cylinder (298 K), pressure (1.034e7 Pa), and the amount of gas (1 mole).

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between pressure, volume, and temperature using the ideal gas law and adiabatic processes. There is uncertainty regarding the assumptions made about volume and the relevance of the adiabatic exponent. Questions arise about the reasonableness of calculated temperatures and the significance of the number of moles in the calculations.

Discussion Status

The discussion is ongoing, with participants providing insights into the relationships between variables and attempting to derive temperatures based on different approaches. Some guidance has been offered regarding the use of adiabatic expansion equations, but there is no explicit consensus on the correctness of the calculations presented.

Contextual Notes

Participants note the absence of certain information, such as the volume of the container, which may impact the calculations. There is also mention of the problem's requirement to consider one mole of gas, leading to questions about its relevance in the context of the equations being used.

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Homework Statement



A compressed cylinder holds nitrogen gas at room temperature. How cold is the gas that is escaping from the cylinder?

T(cylinder) = 298 K
P(cylinder) = 1.034e7 Pa
n = 1

Homework Equations



PV = nRT

The Attempt at a Solution



So since I was not given either the volume of the container or its final volume, I assumed that the initial and final volumes were approximately the same. This may be a fatal flaw to my line of reasoning.

Assuming the above is correct, I said:

P/V = constant , and therefore:

P1/T1 = P2/T2 , where P1 and T1 are the pressure and temperature in the cylinder.

I am not sure if I need the adiabatic exponent of f+2/2 in there somewhere or not. Also, I used P2 = 101.3 kPa and yes I put that into Pa before doing the algebra.

Without the adiabatic exponent, I went through the algebra and found the temperature of the escaping gas is 2.94 K. This to me doesn't seem like a reasonable answer since that is really cold. However, I do not have a good understanding of what is reasonable since I do not know much about gas temperatures.

Any comments on whether or not this is correct or flawed would be greatly appreciated.
 
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In addition to above, there are two equations that I know of but neither of them contain both pressure and volume. They are:

VT^(f/2) = constant

PV^(f+2/2) = constant

I don't know how to get P and T together.
 
Look at it as an adiabatic expansion. That'll give you a relationship between two of the variables. With that relationship along with the ideal gas law, you can solve for the final temp.
 
Okay, I rearranged the equation for adiabatic expansion to get that P^(1-gamma)*T^(gamma) = constant.

Going through the algebra for this, I get that the temperature of the gas being released is about 79 K.

The only thing that is still throwing me off a bit is that the problem explicitly states that the calculation should be for one mole of gas. However, nowhere in my calculations is that value relevant. This makes me think I'm not including everything.

Can anybody confirm this number as correct? Thanks for the advice vela.
 
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