Ideal Gas law and a hot air balloon problem

In summary, the balloon is heated by the sun and the air inside it becomes hot. The pressure of the hot gas pushes up on the balloon, causing it to rise. The balloon is filled with air and the total mass is 500kg. The density of the air is less than the mass of the balloon, so the balloon rises because the pressure of the gas is greater than the weight of the balloon.
  • #1
wilsbran
2
0
My physics problem is as following,
Estimate the average temperature of the air inside a hot air balloon. Assume that the total mass of the unfilled balloon and payload is 500kg. what is the mass of the air inside the balloon?
we are told to use a radius of 15m

Equations needed
density = m/V
ideal gas law PV=nRT
Pressure = Force over area.

This is what i Have so far:

Fnet = Fbuoyant - Fgravity
because the balloon is assumed to be in equilibrium Fnet = zero
0= density*V*g -(mass of air+mass of payload)*g
Its here that i start to get confused. I think that the density is the density of the air alone because it is the buoyant force of the heated air pushing up on the balloon so to speak.
I know that there is a relation to the gas law and from that the temperature of the balloon can be calculated...but i am stuck at this:
P= density*R*T

any suggestions/help?
 
Physics news on Phys.org
  • #2
You can easily find an expression Fbuoyant using Archimedes's principle. What is Fgravity? It's the weight of the unfilled balloon plus the weight of the hot air in it. If you are going to use the ideal gas law (which you should) you need to consider the pressure of the hot gas.
 
  • #3
i have used the expression for the buoyant force

density*V*g = (mass of air+mass of payload)*g -------> eqn (1)

where density*V*g is the the buoyant force

i am having trouble relating it to the gas law. I know that

density = m/V

so PV=nRT can be seen as

P = density*R*T / Molar Mass

but from the force equation (eqn (1) above) i have I'm not sure how to proceed as i do not know the mass of the air.
 
  • #4
The mass of the air is mair=Nm, where N = number of molecules and m = mass of one molecule. Use the ideal gas law in the form pV = NkT to replace N in the mass expressions for the gas inside and outside the balloon.
 
  • #5


I would approach this problem by first defining the variables and equations involved. The ideal gas law, PV=nRT, relates the pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T) of a gas. In this case, the gas in question is air.

Next, I would consider the forces acting on the hot air balloon. As you correctly stated, there is a buoyant force (Fbuoyant) acting upwards due to the heated air inside the balloon, and a gravitational force (Fgravity) acting downwards on the total mass of the balloon and payload. In order for the balloon to be in equilibrium, these two forces must be equal in magnitude.

Using the equation for density (m/V), we can calculate the density of the air inside the balloon as the buoyant force divided by the volume of the balloon. This is the density of the air alone, as you mentioned. We can then substitute this value into the ideal gas law as follows:

P = (m/V) * R * T

We know the pressure (P) is equal to the weight of the balloon and payload divided by the area of the balloon. This is because pressure is defined as force (in this case, weight) divided by area. So we can rearrange this equation to solve for the mass of the air inside the balloon (m):

m = P * V / R * T

We are given the volume of the balloon (V) and the total mass of the balloon and payload (500 kg). We can also look up the value for the gas constant (R = 8.314 J/mol·K). Therefore, we can solve for the temperature (T) by plugging in these values and solving for T.

T = P * V / (m * R)

Once we have calculated the temperature, we can use the ideal gas law to calculate the mass of the air inside the balloon. We can also use this information to estimate the average temperature of the air inside the balloon by assuming that the heated air is at a constant temperature throughout the balloon.

In summary, to solve this problem, we need to use the ideal gas law and the equations for density and pressure to calculate the temperature and mass of the air inside the hot air balloon. I hope this helps!
 

FAQ: Ideal Gas law and a hot air balloon problem

1. What is the Ideal Gas law?

The Ideal Gas law is a mathematical equation that relates the pressure, volume, temperature, and number of moles of an ideal gas. It is written as PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

2. How is the Ideal Gas law applied to a hot air balloon problem?

In a hot air balloon, the ideal gas law is used to determine the amount of gas needed and the temperature required to lift the balloon off the ground. The volume of the balloon is fixed, so the pressure inside the balloon must increase in order to lift it. This is achieved by heating the air inside the balloon, increasing its temperature and thus, its pressure.

3. What are the assumptions of the Ideal Gas law?

The Ideal Gas law assumes that the gas particles have no volume, there are no intermolecular forces between the particles, and the collisions between particles are perfectly elastic. It also assumes that the gas is in a closed system and the temperature is in Kelvin.

4. How does the Ideal Gas law relate to the Kinetic Molecular Theory?

The Ideal Gas law is derived from the Kinetic Molecular Theory, which states that gas particles are in constant random motion and that their kinetic energy is directly proportional to the temperature of the gas. This theory helps to explain the behavior of ideal gases and how they relate to the variables in the Ideal Gas law equation.

5. Can the Ideal Gas law be applied to real gases?

The Ideal Gas law is a simplified model that is most accurate for ideal gases at low pressures and high temperatures. Real gases may deviate from this model due to factors such as intermolecular forces and the volume of gas particles. However, the Ideal Gas law can still be used as an approximation for real gases in most situations.

Similar threads

Replies
1
Views
2K
Replies
1
Views
5K
Replies
14
Views
2K
Replies
5
Views
2K
Replies
4
Views
2K
Replies
2
Views
2K
Back
Top