Identification of a ratio using Refractive indices (RESOLVED)

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SUMMARY

The discussion focuses on calculating the mole fraction (X) of two substances in a mixture using their refractive indices. The refractive indices provided are nmixture=1.4156, nbutan-2-one=1.3787, and ntoluene=1.4970. The key equation used is nmixture = (Xbutan-2-one * nbutan-2-one) + (XToluene * nToluene). The solution involves recognizing that the sum of the mole fractions (Xbutan-2-one + XToluene) equals one, allowing for substitution to solve for the unknowns.

PREREQUISITES
  • Understanding of refractive indices and their significance in mixtures
  • Familiarity with mole fractions and their calculation
  • Basic algebra for solving systems of equations
  • Knowledge of the concept of substitution in mathematical equations
NEXT STEPS
  • Study the principles of refractive index and its application in solution chemistry
  • Learn about the calculation of mole fractions in binary mixtures
  • Explore methods for solving systems of equations, particularly substitution and elimination
  • Investigate the relationship between refractive index and concentration in solutions
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Chemistry students, laboratory technicians, and anyone involved in analytical chemistry or physical chemistry who needs to understand the calculation of mole fractions in mixtures.

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Homework Statement


I need to find the X of two substances using only the data found in lab. Which is: nmixture=1.4156 nbutan-2-one=1.3787
ntoluene=1.4970 For the mixture, I don't know what X (the mole fraction) is. That is what I must find out.

Homework Equations


nmixture= (Xbutan-2-one *nbutan-2-one) + (XToluene *nToluene)

The Attempt at a Solution


IMG_20150906_212558.jpg

What I did here is I said let x be equal to X for the butan-2-one and y be equal to X for the toluene...Then finding two equations to do a substitution...which obviously did not work...I also tried other things that basically ended up worse than this...I'm really stuck and I would need a lead! Thank you in advance for your help :) !
 
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Oh, I actually found the solution... You have to add the X's which equal to one. With the system of equation you can substitute and only then you only have one unknown! (Is there a way to close the thread as it is not useful anymore :) )
 

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