Identifying L_p[-n,n] as a Subspace of L_p(R)

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SUMMARY

The discussion centers on identifying the space L_p[-n, n] as a subspace of L_p(ℝ). It concludes that while a function f in L_p(ℝ) implies its p-power is integrable on any subspace, the reverse is not necessarily true; a function integrable on [-n, n] may not be p-power integrable on all of ℝ. Additionally, the mapping from L_p(ℝ) to L_p[-n, n] is not injective, which further complicates the identification of these spaces. The existence of maps in both directions does not establish a subspace relationship.

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Kreizhn
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I've been given an assignment question, where I've been asked to identify [itex]L_P[-n, n][/itex] as a subpsace of [itex]L_p(\mathbb R)[/itex] in the obvious way. It seems to me though that this may be backwards, as if [itex]f \in L_p( \mathbb R)[/itex] then its p-power should also be integrable on any subspace of [itex]\mathbb R[/itex]. However, a function integrable on [-n,n] may not be p-power integrable on all of R. Do I have this backwards?
 
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Kreizhn said:
a function integrable on [-n,n] may not be p-power integrable on all of R.
Wait a minute -- there isn't a restriction map from {functions on [-n,n]} to {functions on R}... What exactly do you mean here, and is it really what you want?



Incidentally, note that while you defined a map Lp(R) --> Lp[-n,n], it doesn't identify Lp(R) with a subspace of Lp[-n,n], because the map isn't injective.

(But even if you had an injective map, it's perfectly okay for there to exist maps in both directions that make Lp(R) a subspace of Lp[-n,n], and Lp[-n,n] a subspace of Lp(R))
 
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