Identifying Lewis Acids: Examples and Corrections

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The discussion focuses on identifying Lewis acids in various chemical reactions. The correct Lewis acids identified include SO_3, Ca^{+2}, and Al(OH_2)_5OH^{+2} in the first three problems. For the fourth problem, both CaO and H_2O are Lewis acids, with H_2O accepting electrons from CaO. In the final problem, Cl^- and Na^+ are both recognized as Lewis acids, as they accept electrons from H_2O. Understanding that Lewis acids are electron acceptors is crucial for correctly identifying them in reactions.
vsage
It's been awhile since I've done chem and I don't really remember how to identify Lewis Acids too well so here are a few problems I'd like you guys to check over / correct:

CaO(s) + SO_3(g) \rightarrow CaSO_4 My answer: SO_3

Ca^{+2}(aq) + SO_4^{-2}(aq) \rightarrow CaSO_4(s) My answer: Ca^{+2}

Al(OH_2)_6^{+3} + H_2O \rightarrow Al(OH_2)_5OH^{+2} + H_3O^{+} My answer: Al(OH_2)_5OH^{+2}

CaO(s) + H_2O(l) \rightarrow Ca(OH)_2(s). My answer: CaO(s) but there's also another Lewis Acid according to the worksheet

NaCl(s) \rightarrow (H_2O) Na^+(aq) + Cl^-(aq)
My answer: Cl^- but there's another Lewis Acid according to the worksheet

I unfortunately had to miss class for another exam the day of this lecture so I'm pretty clueless! Thanks in advance.
 
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First of all, your answers for the first three problems are correct. SO_3, Ca^{+2}, and Al(OH_2)_5OH^{+2} are all Lewis acids in these reactions.

However, for the fourth problem, your answer is not completely correct. While CaO can act as a Lewis acid in this reaction, there is actually another Lewis acid present as well - H_2O. In this reaction, H_2O acts as a Lewis acid by accepting a lone pair of electrons from CaO to form Ca(OH)_2. So the correct answer would be CaO and H_2O as Lewis acids in this reaction.

For the final problem, your answer is partially correct. Cl^- is indeed a Lewis acid in this reaction as it accepts a lone pair of electrons from H_2O to form HCl. However, there is another Lewis acid present - Na^+. Na^+ acts as a Lewis acid by accepting a lone pair of electrons from H_2O to form NaOH. So the correct answer would be Cl^- and Na^+ as Lewis acids in this reaction.

In summary, it is important to remember that Lewis acids are electron acceptors and can be identified by their ability to accept a lone pair of electrons from a Lewis base. In some cases, there may be multiple Lewis acids present in a reaction. Keep practicing and you will become more confident in identifying Lewis acids!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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