Identifying the Odd Resistor: How Many Measurements Are Needed with an Ohmmeter?

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Homework Help Overview

The discussion revolves around identifying an odd resistor among a set of nine resistors, where all but one have a resistance of 1 ohm. Participants are exploring the minimum number of measurements needed using an ohmmeter to determine which resistor is different.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are considering various strategies for measuring resistances, including measuring resistors one-by-one and grouping them in pairs. There is also discussion about the implications of luck in selecting the odd resistor and the potential for clever measurement strategies.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on measurement strategies and questioning assumptions about the problem. Some guidance has been offered, but there is no explicit consensus on the best approach yet.

Contextual Notes

Participants are navigating the constraints of using only an ohmmeter and the challenge of minimizing measurements while identifying the odd resistor. There is an emphasis on not relying on luck for the solution.

fshiznit
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You receive a box of 9 resistors. All the resistors except one have a value of 1 ohm. With only an ohmmeter, what is the minimum number of measurements needed to identify the odd resistor and find its resistance.

-I've tried going up from one resistor, but I'm not sure what I'm doing past 4 resistors :S..any help is much appreciated!
 
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fshiznit said:
-I've tried going up from one resistor, but I'm not sure what I'm doing past 4 resistors :S..any help is much appreciated!
What do you mean by "going up from one resistor"? Please be more explicit in your explanation.
 
so for let's say 3 resistors, you'll need two measurements because say you take an even one and an odd one and get a resistance of 2.1 ohm (that's one measurement) then you take one off to which is the odd one and its resistance (second measurement). but now I am thinking, wouldn't the minimum measurements, even for the 9 resistor one, be just two measurements, seeing that you get lucky and pick the odd one when testing the first two resistors? But then i guess the question'd be too easy :S
 
As I interpret the question, assuming you are unlucky, what is the minimum number of measurements required?

A naive approach would be to measure them one-by-one and the odd one is the last resistor. However, you have to be a little clever here. Other than measuring one at a time, how else might you approach the problem?
 
would it make sense to put them in groups of 2 in parallel? (thus making 4 groups in series). Would that not only take a max. of 5 measurements depending on your luck?
 
Hint: measure resistances across multiple elements at once and think about what that tells you. You cannot rely on luck to get the minimum number of measurements.
 
FYI to everybody:

We really should let fshiznit try to solve the problem, and let him/her respond with questions, before giving further help.
 

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