If a complex converges, then it's conjugate converges.

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    Complex Conjugate
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SUMMARY

The discussion centers on proving that if a sequence of complex numbers \( z_n \) converges to \( z_0 \), then the sequence of their conjugates \( \overline{z_n} \) converges to \( \overline{z_0} \) as \( n \) approaches infinity. The proof utilizes properties of absolute values and the triangle inequality, specifically demonstrating that \( |\overline{z_n} - \overline{z_0}| = |z_n - z_0| \). The notation for complex conjugation is clarified, with a preference for using '*' over '~'.

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Homework Statement



Prove that z_n -> z_0 if and only if ~(z_n) -> ~(z_0) as n goes to infiinity.

~(z_n) is the conjugate of z_n.


Homework Equations





The Attempt at a Solution



|~(z_n) - ~(z_0) | = | ~(z_n) + ~(-z_0)| <=

|~(z_n)| + |~(-z_0) | = |z_n| + |z_0| <=

and I can't come up with much else. It's about the same for the other direction as well.
 
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Using a '*' for complex conjugation is more usual than '~'. |z*|=|z|.
|z_n*-z_0*|=|(z_n-z_0)*|=|z_n-z_0|. Use stuff like that. Now write it in the form of a proof about limits.
 
Dick said:
Using a '*' for complex conjugation is more usual than '~'.

* looks better after seeing it. I just couldn't think of a way the first time around.
 

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