Is a Point Inside a Tilted Cube?

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To determine if a point is inside a tilted cube, first establish the cube's fixed dimensions and its ability to rotate around its edges or corners. The problem involves checking if a point (x, y, z) lies within the cube's boundaries after it has been oriented in space. A recommended approach is to rotate the coordinate system so that the cube's sides align with the axes. Once transformed, verify that the point's coordinates fall within the limits defined by the cube's dimensions. This method effectively simplifies the problem of checking point containment in a tilted cube.
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I'm trying to figure out if a point is in a cube that could be tilted in any direction.
How would I do it? I can get anything you need for this problem.

Thanks in advance.
 
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I assume your cube is of fixed dimensions, but free to rotate/tilt about any of its initial edges/corners?
 
arildno said:
I assume your cube is of fixed dimensions, but free to rotate/tilt about any of its initial edges/corners?

Yep.
 
I don't fully understand the question.

Are you saying you have a cube with a known orientation (eg. you are given a unit vector normal to a surface, and the cube centre is fixed at (0, 0, 0)), and want to know if a general point (x, y, z) is in that cube?

Try to develop a method of rotating the coordinate system from the original one to one where the cube sides are perpendicular to the coordinate axes. Then all you need to do is transform your point to this system and ensure it is between each side along all three dimensions.
 
Good morning I have been refreshing my memory about Leibniz differentiation of integrals and found some useful videos from digital-university.org on YouTube. Although the audio quality is poor and the speaker proceeds a bit slowly, the explanations and processes are clear. However, it seems that one video in the Leibniz rule series is missing. While the videos are still present on YouTube, the referring website no longer exists but is preserved on the internet archive...

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