If your not the same person..then well someone got the same problem as you =P

  • Context: Undergrad 
  • Thread starter Thread starter Kerbox
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    Integral
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Discussion Overview

The discussion revolves around solving the integral \(\int \frac{x}{1+\sqrt{x}} dx\). Participants explore various methods and substitutions to approach the problem, sharing their attempts and challenges in finding a solution.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Kerbox requests hints for solving the integral and mentions trying substitutions without success.
  • One participant suggests the substitution \(1+\sqrt{x} = t\).
  • Kerbox responds that the substitution leads to an expression where \(x\) cannot be canceled, indicating a potential misunderstanding or oversight.
  • Another participant encourages Kerbox to post their steps to identify any mistakes in their approach.
  • One participant notes that \(x\) can be expressed as \((t - 1)^2\) based on the substitution.
  • A suggestion is made to use the residue theorem from complex analysis, although another participant points out that this theorem does not apply to antiderivatives.
  • A participant claims to have previously assisted someone with the same integral on another forum, suggesting a possible identity between users.

Areas of Agreement / Disagreement

Participants express differing views on the effectiveness of the proposed substitution and the applicability of the residue theorem, indicating that the discussion remains unresolved with multiple competing approaches.

Contextual Notes

Some assumptions about the integral and the validity of the proposed methods are not fully explored, and there are unresolved steps in the mathematical reasoning presented.

Kerbox
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Hey guys,

I could really use some hints on how to solve the integral \int \frac{x}{1+\sqrt{x}} dx
I tried some substitutions, and doing some manipulations on the expression, with no solution. Any help would be much appreciated.

Regards,

Kerbox
 
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1+\sqrt{x} = t
 
yea, tried that. but I end up with an expression where x can't be canceled. unless I am missing something here.
 
Post your steps, and we can see if you made a mistake.
 
Notice that x = (t - 1)^2.
 
you could use the residue theorem from complex analysis (I think)
 
thebuttonfreak said:
you could use the residue theorem from complex analysis (I think)

The residue theorem does not pertain to antiderivatives.
 
I helped someone else on exactly the same integral in scienceforums.net and I have a really good feeling your the same person, since your post is identical..and your username is the same >.<

Just incase..: http://www.scienceforums.net/forum/showthread.php?t=24664

My name in scienceforums.net is Ragib btw.
 

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