- Problem Statement
- Given a function, f(x)=(8-3x^2)^-(⅓), find the 4 terms of that function's binomial expansion and then represent that expansion as a sum

- Relevant Equations
- f(x)=(8-3x^2)^-(⅓), (1+x)^n=1+nx+n(n-1)(x^2)/2!+n(n-1)(n-2)(x^3)/3!

I found the first 4 terms of the series: ½-(1/16)x^2+(1/64)x^4-(7/1536)x^6.

I cannot however simplify this to a sum. the 7 in the numerator of the last term of the above expansion is the sticking point.

I cannot however simplify this to a sum. the 7 in the numerator of the last term of the above expansion is the sticking point.