# Im ready for this test except I cant get started on these 2 questions.

• davie08
It's good that you've grasped some of the concepts behind vector addition, so you should be able to solve for the sin and cos of angles without much trouble. All in all, I think this problem should be easy for you.f

## Homework Statement

A force of 20N,180degrees (W) and 30N,-110degrees (S20degrees (W) ) are both acting on a 3.0kg mass at rest. If there is 10N of friction:calculate the acceleration.

## Homework Equations

I think you just need kinematic equations so here they are:
V2=V1+a*t
d=V1t+1/2a*t^2

## The Attempt at a Solution

Im going to try the R theta and change that to x and y I just wanted to put this up first stop me if this is wrong.

wait you need forces equations:
Fn=m*a
Fn=Fa+Ff
Fg=m*g
Ff=m*F perpendicular sign

A force of 20N,180degrees (W) and 30N,-110degrees (S20degrees (W) ) are both acting on a 3.0kg mass at rest.
What's the total applied force?
If there is 10N of friction:
Which way does the friction act?
calculate the acceleration.
First find the net force acting on the mass.

well the friction would be negative right since its going against the object

oh wait the total applied force are the first numbers

so I use Fn=Fa+Ff how do I change the first numbers into something I can use

how do I change the first numbers into something I can use
To add the two applied forces, first break them into their components. Then you can add the components and find the new resultant.

im not sure how you chnge them don't you just use pol on the calculator and then F to get them but what about the S20degrees (W)

This problem I think is a little easier than you're making it. You started on the correct approach. Break each force into it's components. Add the two forces together to get the resultant components. From these forces, calculate the resultant force vector.

You now have a force mangitude and direction. Focus for a moment on the magnitude. You're given the friction force. This force acts opposite of motion, so you don't need to worry about direction. Simply subtract the friction force from the total resultant force.

You now have a resultant force and direction; divide by mass to get acceleration. I get 10.45 m/s² as the magnitude of the acceleration. Remember acceleration is a vector, you'll need to specify the direction as well.

im not sure how you chnge them don't you just use pol on the calculator and then F to get them but what about the S20degrees (W)

You shouldn't really need a calculator to break a vector into its components. Just trigonometry. Well, I guess you'll need the calculator to solve for the sin and cos of the angles...

Breaking up a vector into its components should be second nature by this point in the semester/school year.

using that pol F stuff makes it 10 times easier

im just going to hope this isn't on the test lol I actually understand most of this unit now so I should be ok on the test

First of all, you need to take heed of what Jack said. Breaking vectors into components needs to be second nature by now. You can't always rely on calculator to add things in polar coordinates, hell you can't always use a calculator.