Projectiles Problem: Solve Questions & Improve Test Scores

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SUMMARY

The discussion focuses on solving projectile motion problems involving a rock and a golf ball. For the first problem, the rock's horizontal velocity remains constant at 41 m/s, while its vertical velocity after 5.3 seconds is calculated using the formula v2 = v1 + (a)(t), resulting in a total velocity of approximately 81.81 m/s. In the second problem, the golf ball's initial vertical and horizontal components are determined using its launch angle of 22 degrees and initial speed of 15 m/s, allowing for the calculation of horizontal distance traveled before hitting the ground from a height of 25 meters.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Knowledge of vector components in physics
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the derivation and application of kinematic equations in projectile motion
  • Learn how to resolve vectors into horizontal and vertical components
  • Explore the effects of air resistance on projectile motion
  • Practice solving various projectile motion problems with different angles and initial speeds
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Students studying physics, educators teaching projectile motion concepts, and anyone preparing for tests in mechanics or kinematics.

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Homework Statement


just got back my test and did really bad on it. how would you do these question?

1) A rock is fired horizontally off of a cliff at 41 m/s. what is the magnitude of its velocity 5.3s later?

2) a golf ball is thrown out of a window at 15 m/s at an angle of 22* above the horizontal. how far does the golf ball travel horizontally if the window is 25m high?

Homework Equations





The Attempt at a Solution



1) i use this formula v2=v1+(a)(t) and got 81.81m/s

2) blank=/
 
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For 1, you should consider the horizontal and vertical components of the velocity separately. Assuming that there is no air resistance, the horizontal speed will always be 41 m/s. The vertical speed is initially 0 m/s and is increasing at a rate of 9.8 m/s2, and will therefore be v2=9.8*5.3 = 51.94 m/s after 5.3 seconds has passed. The total resultant speed can then easily be calculated.

For 2, draw a diagram if it helps. First calculate the initial vertical and horizontal components of the velocity using the initial speed and angle of projection. You can then use the vertical speed to calculate how long the ball moves before it hits the ground, and then use this time of flight to find how far horizontally it travels (remember, assuming that there is no air resistance, the horizontal velocity does not change).
 

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