Hi all,(adsbygoogle = window.adsbygoogle || []).push({});

If a square matrix A of dimension n*n is a nilpotent matrix,i.e, A^k=0 for k>=m iff A has eigenvalues 0 with multiplicity n and index m or less. I did prove by induction if A^k=0 then all the eigenvalues are zero. I'm lost when I want to prove the oppesite, i.e, if all eigenvalues are zero then A^k=0? Please help

**Physics Forums - The Fusion of Science and Community**

# I'm stuck to prove Nilpotent Matrix

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: I'm stuck to prove Nilpotent Matrix

Loading...

**Physics Forums - The Fusion of Science and Community**