Image of an Object Inside Hollow Glass Sphere

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SUMMARY

The discussion centers on a physics problem from the 1990 Turkey National Physics Olympics involving a hollow spherical glass lens system. The objective is to determine the index of refraction of the glass required for an image of an object on the inner surface to be R/5 away from the object for an observer. The solution indicates that the index of refraction (n) is 2 and the focal length (f) is 4R, derived using the Thin Lens Equation and Lensmaker's Equation. A participant noted inaccuracies in their initial calculations and was advised to consider the thick lens formula instead of the thin lens formula due to the system's complexity.

PREREQUISITES
  • Understanding of the Thin Lens Equation
  • Familiarity with the Lensmaker's Equation
  • Knowledge of optical systems and refraction principles
  • Concept of thick versus thin lenses
NEXT STEPS
  • Study the derivation and applications of the Thick Lens Formula
  • Explore advanced optics concepts such as spherical aberration
  • Learn about the behavior of light in complex lens systems
  • Investigate practical applications of refraction in optical devices
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Students preparing for physics competitions, educators teaching optics, and anyone interested in advanced optical systems and their calculations.

Kaan99
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Hello,
This question is from 1990 Turkey National Physics Olympics. I tried my best to translate it clearly.

1. Homework Statement

https://s23.postimg.org/cotn29afv/Hollow+Spherical+Glass.jpg

The sphere of radius 2R has an empty sphere inside with radius R. In order for the image of an object on the inner surface of the sphere to be R/5 far away from the object (which is shown with an asterisk*) for an observer at the indicated position (göz), what should be the index of refraction of the glass? Where is the focal point of this optical system?

Homework Equations


Thin Lens Equation
Lensmaker's Equation

The Attempt at a Solution


The lens is made up of to circles of radii R and 2R, using lensmaker and thin lens eq.
## \frac{1}{f} = (n-1) (\frac{1}{R_1}-\frac{1}{R_2})=\frac{1}{d_o}+\frac{1}{d_i}##
## (n-1)(\frac{1}{-R}-\frac{1}{-2R})=\frac{1}{2R}+\frac{1}{d_i}##
## \frac{n-1}{-2R}=\frac{1}{2R}+\frac{1}{d_i}##
## d_i=\frac{n}{-2R}##

It turned out that my attempt wasn't accurate from the start, as it deviates from the solution provided. I couldn't understand how the first equation is formed in the solution.

The result is n=2 and f=4R.
 
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Kaan99 said:

The Attempt at a Solution


The lens is made up of to circles of radii R and 2R, using lensmaker and thin lens eq.
1f=(n−1)(1R1−1R2)=1do+1di1f=(n−1)(1R1−1R2)=1do+1di \frac{1}{f} = (n-1) (\frac{1}{R_1}-\frac{1}{R_2})=\frac{1}{d_o}+\frac{1}{d_i}
(n−1)(1−R−1−2R)=12R+1di(n−1)(1−R−1−2R)=12R+1di (n-1)(\frac{1}{-R}-\frac{1}{-2R})=\frac{1}{2R}+\frac{1}{d_i}
n−1−2R=12R+1din−1−2R=12R+1di \frac{n-1}{-2R}=\frac{1}{2R}+\frac{1}{d_i}
di=n−2Rdi=n−2R d_i=\frac{n}{-2R}

It turned out that my attempt wasn't accurate from the start, as it deviates from the solution provided. I couldn't understand how the first equation is formed in the solution.
Kaan99 said:
Hello,
This question is from 1990 Turkey National Physics Olympics. I tried my best to translate it clearly.
i think you have a very thick lens system so your thin lens formula will not work.
search in the textbook for thick lens formula.
 

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