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Optics: Half Lens in the Air, Half Lens in Water.

  1. Jun 1, 2017 #1
    1. The problem statement, all variables and given/known data
    Hello everybody! One surface of a biconvex lens (n=1,5) is in the air (na=1) while the other surface is dipped in the water (nw=4/3). If the power of the lens in the air is Po=10 Dioptri, The lens power in such condition is?

    2. Relevant equations
    Lensmaker Equation
    Pl=((n2/n1)-1).{(1/R1)-(1/R2)}

    3. The attempt at a solution
    I've tried to derived the lensmaker equation for three medium using geometry resulting in (P=[n1/do]+[n3/di]). Since there is no given distance of object nor distance of the image, I do not know how to work this problem out.
     
  2. jcsd
  3. Jun 1, 2017 #2

    haruspex

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    Try considering the lens as two planoconvex lenses together. Do you know how to calculate the power of two lenses in series?
     
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