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Momentum transfer after 10kg ball hit is 100 kg-m/s, the 100kg ball's velocity is ~.0909m/s or 1m/s.It may help to start with a very simple problem. If a 10 kg ball moving at 10 m/s has a perfectly inelastic collision with a stationary 100 kg ball, do you know how to find the velocity of the two balls after the collision?

okay, well...Imma just come straight. The idea is like a baseball hitting a glove or a hammer hitting a nail or as I just did, a thrown at a nail. I forgot to add Mechanical energy(because I forgot).

TMEi + Wext = TMEf ; if we have really tough objects or psuedo-rigid

If I throw a ball at a catchers glove, the catchers glove exerts 500 Newtons at opposite to my incoming ball which I threw

The ball has 30 joules, without to much calculations lets say the glove is displaced .045 meters, we will say this is our final displacement; KE=TMEi

(30Joules)+(-500N's•.045 meters) = TMEf= 7.5 Joules, the 7.5 joules is expended into deformation and heat,etc