Implicit derivative difficulties

Click For Summary
SUMMARY

The discussion focuses on solving implicit derivatives, specifically for the equation \(\frac{x+3}{y} = 4x + y^2\). The user struggles to isolate \(y'\) after differentiating both sides, leading to a complex expression that includes \(y'\) on both sides. The provided solution in the course book is \(y' = \frac{y - 4y^2}{x + 3 + 2y^3}\). The key takeaway is to move all terms containing \(y'\) to one side and factor \(y'\) out to simplify the equation.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with basic calculus concepts such as derivatives
  • Knowledge of algebraic manipulation techniques
  • Experience with solving equations involving multiple variables
NEXT STEPS
  • Practice implicit differentiation with various equations
  • Learn how to factor expressions involving derivatives
  • Explore the application of implicit differentiation in real-world problems
  • Review calculus textbooks focusing on implicit functions and derivatives
USEFUL FOR

Students studying calculus, particularly those encountering challenges with implicit differentiation, as well as educators seeking to clarify these concepts for their students.

kald13
Messages
9
Reaction score
0

Homework Statement



I am struggling with implicit derivatives, and though my course book includes final solutions to odd numbered exercises, it does not show the work. As such, I'm stuck in the process of getting from point A to point B:

Find the derivative y'(x) implicitly of

[itex]((x+3)/y)=4x+y^2[/itex]

2. The attempt at a solution

I know to start with the derivative of each side of the equation:

[itex]((d/dx)[x+3]y-(x+3)(d/dx)[y])/y^2=(d/dx)[4x+y^2][/itex]
[itex]((1)y-(x+3)(y'))/y^2=4+2y(y')[/itex]

Multiply both sides by [itex]y^2[/itex]

[itex]y-y'(x+3)=4y^2+2y^3(y')[/itex]

Subtract [itex]y[/itex] and then divide both sides by [itex]-(x+3)[/itex]

[itex]-y'(x+3)=4y^2-y+2y^3(y')[/itex]
[itex]y'=-(4y^2-y+2y^3(y'))/(x+3)[/itex]

So now I have y' isolated on the left, but I still have a y' on the right that doesn't factor, and I'm not sure what to do with it. I run into a similar problem if I try to isolate y' on the right first, and I'm not sure how to procede from this point.

The solution provided in the book is:

[itex]y'=(y-4y^2)/(x+3+2y^3)[/itex]

Getting close, but not quite there.
 
Physics news on Phys.org
kald13 said:

Homework Statement



I am struggling with implicit derivatives, and though my course book includes final solutions to odd numbered exercises, it does not show the work. As such, I'm stuck in the process of getting from point A to point B:

Find the derivative y'(x) implicitly of

[itex]((x+3)/y)=4x+y^2[/itex]

2. The attempt at a solution

I know to start with the derivative of each side of the equation:

[itex]((d/dx)[x+3]y-(x+3)(d/dx)[y])/y^2=(d/dx)[4x+y^2][/itex]
[itex]((1)y-(x+3)(y'))/y^2=4+2y(y')[/itex]

Multiply both sides by [itex]y^2[/itex]

[itex]y-y'(x+3)=4y^2+2y^3(y')[/itex]

Subtract [itex]y[/itex] and then divide both sides by [itex]-(x+3)[/itex]

[itex]-y'(x+3)=4y^2-y+2y^3(y')[/itex]
[itex]y'=-(4y^2-y+2y^3(y'))/(x+3)[/itex]

So now I have y' isolated on the left, but I still have a y' on the right that doesn't factor, and I'm not sure what to do with it. I run into a similar problem if I try to isolate y' on the right first, and I'm not sure how to procede from this point.

The solution provided in the book is:

[itex]y'=(y-4y^2)/(x+3+2y^3)[/itex]

Getting close, but not quite there.

Starting from ##y-y'(x+3)=4y^2+2y^3(y')## move all of the terms containing y' to one side and factor y' out before you do anything else.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
2K
  • · Replies 24 ·
Replies
24
Views
3K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K