Implicit Differentiation of tan(x-y) and Solving for y' | Step-by-Step Guide"

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SUMMARY

The discussion focuses on the implicit differentiation of the equation tan(x-y) = y/(1+x²) and solving for y'. The derivative is calculated using the chain rule and product rule, resulting in the equation sec²(x-y)(1-y') = [(1+x²)y' - 2xy]/(1+x²)². Participants confirm the correctness of the differentiation process and provide insights into rearranging the equation to isolate y'.

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  • Understanding of implicit differentiation
  • Familiarity with trigonometric functions, specifically tangent
  • Knowledge of the chain rule and product rule in calculus
  • Basic algebraic manipulation skills
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  • Study the application of the chain rule in implicit differentiation
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Students and educators in calculus, mathematicians focusing on differential equations, and anyone seeking to enhance their understanding of implicit differentiation techniques.

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tan(x-y)=y/(1+x2)

When I take the derivatives of both sides, I get:
sec2(x-y)(1-y')=[(1+x2)y'-2xy]/(1+x2)2
 
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