Implicit Differentiation: Solving for dy/dx

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SUMMARY

The discussion centers on implicit differentiation, specifically solving for dy/dx in the equation x^2 + 2xy - y^2 + x^2 = 2. The correct derivative is derived as dy/dx = (-4x - 2y) / (2x - 2y), which can be simplified to dy/dx = (y + 2x) / (y - x) for a more aesthetically pleasing form. Participants confirm the accuracy of the calculations and provide a simplified expression for clarity.

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  • Understanding of implicit differentiation
  • Familiarity with algebraic manipulation
  • Knowledge of derivatives and their notation
  • Basic skills in solving equations
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  • Study the concept of implicit differentiation in calculus
  • Practice simplifying derivatives using algebraic techniques
  • Explore applications of implicit differentiation in real-world problems
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Students studying calculus, educators teaching implicit differentiation, and anyone looking to enhance their understanding of derivatives and algebraic manipulation.

la_med12
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1.
I'm pretty sure I've got this right.. just needing a check. Cheers!

2.
x^2+2xy-y^2+x^2=2

3.
2x+2x(dy/dx)+2y-2y(dy/dx)+2x=0
2x(dy/dx)-2y(dy/dx)=-4x-2y
dy/dx(2x-2y)=-4x-2y
dy/dx=(-4x-2y)/(2x-2y)
 
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Correct, but you can factorise and multiply top and bottom by -1 to become
[tex]\frac{dy}{dx} = \frac{y+2x}{y-x}[/tex]
which looks nicer. :smile:
 
Last edited:
Thanks for the check.

Cheers!
 

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