Improper integral concept question

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SUMMARY

The integral \(\int_0^K \frac{x^2}{x^2-19x+90} dx\) is improper for values of \(K\) that cause the integrand to be undefined or infinite. Specifically, the integral becomes improper when \(K < 10\) or \(K = 9\) since the denominator \(x^2 - 19x + 90\) equals zero at \(x = 9\) and \(x = 10\). The discussion emphasizes the need for partial fraction decomposition to evaluate the integral correctly and highlights that logarithmic functions are undefined for values less than 1.

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  • Basic calculus concepts, including integration techniques
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Students studying calculus, particularly those focusing on integration techniques, and educators seeking to clarify the concept of improper integrals.

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Homework Statement



For what values of K is the following integral improper?

[tex]\int\stackrel{K}{0}x^2 / (x^2-19x+90) dx[/tex]I'm stuck on this question. I understand mechanically, that the integration require partial fraction decomp, which results in -9ln(x-9) (from 0 to K) + 10ln(x-10) (from 0 to K). What I don't understand is what makes this integral improper. I understand that LN is undefined for all evaluations < 1. So does this mean that any K < 10 will create an improper integral?

EDIT: How does one properly display the upper and lower limits on the integration symbol?
 
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wetwilly92 said:

Homework Statement



For what values of K is the following integral improper?

[tex]\int\stackrel{K}{0}x^2 / (x^2-19x+90) dx[/tex]I'm stuck on this question. I understand mechanically, that the integration require partial fraction decomp, which results in -9ln(x-9) (from 0 to K) + 10ln(x-10) (from 0 to K). What I don't understand is what makes this integral improper. I understand that LN is undefined for all evaluations < 1. So does this mean that any K < 10 will create an improper integral?

EDIT: How does one properly display the upper and lower limits on the integration symbol?

To get the limits right use \int_0^K instead of stackrel.

As for the question itself, you might want to draw a sketch of the function.
 
An integral may be "improper" for one of several reasons-
1) The lower limit is [itex]-\infty[/itex].
2) The upper limit is [itex]\infty[/itex].
3) The integrand goes to [itex]-\infty[/itex] at some point in the interval of integration.
4) The integrand goes to [itex]\infty[/itex] at some point in the interval of integration.

Which of those can happen here?

What values of x make the denominator of the integrand 0?
 

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