Impulse and Momentum (finding net force)

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To find the impulse of the net force on a 0.500-kg ball dropped from 1.20 m and rebounding to 0.700 m, one must calculate the change in momentum, which requires determining the ball's speed just before and after the impact. The speed before impact can be calculated using potential energy at the drop height, while the speed after impact can be derived from the rebound height. The discrepancy in expected results, with values of 3.1305 instead of the anticipated 4.28, suggests a potential miscalculation in these speed determinations. Accurate calculations of these speeds are essential for resolving the impulse value. Understanding the relationship between height, potential energy, and kinetic energy is crucial for solving this problem correctly.
acra
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A 0.500-kg ball is dropped from rest at a point 1.20 m above the floor. The ball reboundes straight upward to a height of 0.700 m. What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor?

I have been trying to solve this various ways, I have tried using PE and KE, but I keep on coming up with 3.1305 instead of the 4.28 which I should be getting.

Any guidance would be greatly appreciated.
 
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acra said:
A 0.500-kg ball is dropped from rest at a point 1.20 m above the floor. The ball reboundes straight upward to a height of 0.700 m. What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor?

I have been trying to solve this various ways, I have tried using PE and KE, but I keep on coming up with 3.1305 instead of the 4.28 which I should be getting.

Any guidance would be greatly appreciated.
You have to determine the ball's change in momentum. To do that you need to know its speed immediately before and immediately after the impact with the floor.

Can you determine these speeds from the two heights given?

AM
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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