Question: A 500 g cart is released from rest 1.0 m from the bottom of a frictionless, 30 degrees ramp. The cart rolls down the ramp and bounces off a rubber block at the bottom. During collision, the cart and the ramp are in contact for 0.0267 sec. The average force exerted by the ramp on the cart is 100 N. After the cart bounces, how far does it roll back up the ramp?(adsbygoogle = window.adsbygoogle || []).push({});

To solve this problem, do I need to find magnitude and direction of initial force of the cart first, and then subtract this from the force that the ramp exerts in opposite direction at the bottom to give impulse? I am confused. Any help would be greatly appreciated.

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# Homework Help: Impulse and momentum of a cart down a ramp

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